法1
#include <iostream>
using namespace std;
void main()
{
int k=0;
while(k<5)
{
for(int i=1;i<=9;i++)
{
for(int j=2+k;j<6+k;j++)
cout<<j<<" x "<<i<<" = "<<j*i<<'\t';
cout<<endl;
}
cout<<endl;
k += 4;
}
}
法2
#include "stdafx.h"
int _tmain(int argc, _TCHAR* argv[])
{
for(int x=1;x<=9;x++){for(int y=2;y<=5;y++){printf("%d*%d=%2d\t",y,x,x*y);}printf("\n");}printf("\n");
for(int a=1;a<=9;a++){for(int b=6;b<=9;b++){printf("%d*%d=%2d\t",b,a,a*b);}printf("\n");}
return 0;
}
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